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Date:	Mon, 13 May 2002 08:07:23 +0300 (IDT)
From:	Eli Zaretskii <eliz AT is DOT elta DOT co DOT il>
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To:	"Rafal 'Raf256' Maj" <admin AT raf256 DOT com>
cc:	djgpp AT delorie DOT com
Subject:	Re: 0xB800:0000 = ... ;
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On 12 May 2002, Rafal 'Raf256' Maj wrote:

> what is the fastest way in DJGPP to access conventional memory (video ram) 

It depends on your video and other hardware, not only on the programmatic 
technique.

In general, I recommend farptr functions, see sections 10.2 and 18.4 of 
the DJGPP FAQ for details.

> how can I write it, like :
> (unsigned char*)(0xB800:x) = a;
> 
> and read it
> a = (unsigned char*)(0xB800:x);

Use nearptr method; see section 18.6 of the FAQ for more.

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