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From:	degoble AT gtech (David. E. Goble)
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: *Newbie= Why isn't this small function working correctly?
Date:	Thu, 20 Dec 2001 02:58:23 GMT
Organization:	Gtech.Computing
Message-ID:	<3c21516d.11484318@gtech>
References:	<20011218200551 DOT 38218 DOT qmail AT web13907 DOT mail DOT yahoo DOT com>
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To:	djgpp AT delorie DOT com
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On Tue, 18 Dec 2001 12:05:51 -0800 (PST), Chris Amos
<homie_dont_play_dat AT yahoo DOT com> wrote:
>
>void getstr(const char *string, const char *new_string, int
>start_offset, int end_offset);
>
Iam a newbe, so I may get somethings wrong.

Why declare the function then, define it, just have the function above
main.
>
>/**************************************************************************/
>void getstr(const char *string, const char *new_string, int
>start_offset, int end_offset)
>
Does declaring a const .... make the parameter readonly (ie
unchangable)???
>
>{
>  int i=0;
>  int b=0;
>
>  for (i=start_offset; i<=end_offset; i++) {
>    *(new_string+b)=string+i;
>    b++;
>  }
>  *(new_string+b)='\0';
>  return;
>
Syntax of return is return exp;

The function is declared to return void (ie it does not return
anything), so no need of return anyway.

Just my Aus 2 cents...

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