From:	"Jason Yip" <manman AT netteens DOT net>
Newsgroups:	comp.os.msdos.djgpp
Subject:	"-1" cannot quite the prog..
Date:	Tue, 7 Dec 1999 23:37:24 +0800
Organization:	netteens.net (Hongkong Telecom IMS)
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To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp
Reply-To:	djgpp AT delorie DOT com

I wrote this prog and expect it can be quited by entering -1...
however it shows wrong if I enter "-1"...
What's more, when I enter a wrong answer.. the answer will never be correct
again...
I wonder why it acts like this...
Can anyone helps me? Thx..

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
main ()
{
int ans,h,a,b;
printf("Enter -1 to end\n");
do{
srand(time(NULL));
a=1+(rand()%9);
b=1+(rand()%9);
printf("How much is %d times %d? ",a,b);
ans=a*b;
scanf("%d",&h);
        if (ans == h || h != -1)
        printf("Very Good!\n");
        else
        if (ans != h || h != -1){
        do{{
        printf("No. Please try again.\n");
        printf("? ");
        scanf("%d",&h);}
        if (ans == h || h != -1)
        printf("Very Good!\n");} while (ans != h || h != -1);
        }} while (h != -1);
        if (h == -1)
 printf("That's all for now. Bye.");
return 0;
}

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