Date:	Thu, 7 Oct 1999 19:01:15 +0200 (IST)
From:	Eli Zaretskii <eliz AT is DOT elta DOT co DOT il>
X-Sender:	eliz AT is
To:	Tim Bedding <tim AT polyhedra DOT com>
cc:	"'djgpp AT delorie DOT com'" <djgpp AT delorie DOT com>
Subject:	Re: Problems using signals
In-Reply-To:	<01BF10C3.98917580@tim.polyhedra.com>
Message-ID:	<Pine.SUN.3.91.991007185238.24155I-100000@is>
MIME-Version:	1.0
Reply-To:	djgpp AT delorie DOT com
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On Thu, 7 Oct 1999, Tim Bedding wrote:

> Due to a mistake, I ran a program containing
> a tight loop. This simple program did not explicitly define
> or call any signal functions.
> 
> I could not interrupt the program using Ctrl-C.
> 
> Is this to be expected?

Yes.  The DJGPP signal-generation doesn't work if/when the program is 
stuck in a tight loop that doesn't touch any data, and when the program 
is inside a call to any real-mode service (DOS, BIOS, etc.).

This is described in the docs (see the documentation of the library 
function `signal', under "Signal Mechanism Implementation Notes").

> Is there a way to program
> or compile in order to make sure that the program
> is always interruptable somehow?

I'm not aware of any way to do that, except avoiding tight loops that 
don't touch any data, and are infinite loops on top of that ;-)

Sorry, the DPMI spec simply doesn't leave any other safe way of 
supporting signals.

> I have read the info documentation of the signal function.

Then I don't understand how come you didn't know this is expected 
behavior.  Unless you have an old libc.info file from DJGPP v2.01, that 
is.

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