www.delorie.com/archives/browse.cgi   search  
Mail Archives: djgpp/1999/08/13/15:53:09

From: "Nick" <nick AT selectrec DOT net>
Newsgroups: comp.os.msdos.djgpp
Subject: From Bytes to Int and Char
Lines: 21
X-Newsreader: Microsoft Outlook Express 4.71.1712.3
X-MimeOLE: Produced By Microsoft MimeOLE V4.71.1712.3
Message-ID: <rfXs3.4$bZ1.1603@typhoon01.swbell.net>
Date: Fri, 13 Aug 1999 10:53:25 -0500
NNTP-Posting-Host: 209.184.56.83
X-Complaints-To: abuse AT swbell DOT net
X-Trace: typhoon01.swbell.net 934559831 209.184.56.83 (Fri, 13 Aug 1999 08:57:11 PDT)
NNTP-Posting-Date: Fri, 13 Aug 1999 08:57:11 PDT
Organization: SBC Internet Services
To: djgpp AT delorie DOT com
DJ-Gateway: from newsgroup comp.os.msdos.djgpp
Reply-To: djgpp AT delorie DOT com

I am trying to load some data from a files, the 6 and 7th bytes are an
Integer and so are the 11th and 12th.  How do I make them into an INT?  This
is what I used earlier

char ver, type;
int sz, tz;

ver = file_buffer[0];
type = file_buffer[1];
.
.
.
sz = file_buffer[6] + file_buffer[7];

is that right?
TIA...

                                                                            
                        -/\/ick


- Raw text -


  webmaster     delorie software   privacy  
  Copyright © 2019   by DJ Delorie     Updated Jul 2019