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From: | "Michael Stewart" <mike AT reggin DOT freeserve DOT co DOT uk> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: Using pointers |
Date: | Fri, 7 May 1999 08:42:47 +0100 |
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To: | djgpp AT delorie DOT com |
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GiovanniB wrote in message ... > > When I declare a pointer (i.e. int* myptr) it's possible to use it in >this way : > for(int i = 0; i < n; i++) > { > myptr[i] = somenumber; > } >where n is a number big than biggest int ? You can indeed treat a pointer as an array, in a sense thats what it is. Just remember to allocate the memory. /* C */ myptr = (int *) malloc (n * sizeof (int)); /* C++, I think this is how to do it */ myptr = new (int)[n]; Michael Stewart
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