From:	Klaus Petzold <califax AT wupperonline DOT de>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Why GPF?
Date:	Sun, 27 Sep 1998 16:24:57 +0100
Organization:	Customer of SpaceNet GmbH
Lines:	46
Message-ID:	<360E58C8.1F87EAD1@wupperonline.de>
NNTP-Posting-Host:	line7.kdt.de
Mime-Version:	1.0
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

Hi,

I get a General Protection Fault when I run the following
program under DJGPP. But why is "t" not allowed to access
"a" via "*t"? Is there a way to get around this problem?

tia
  Klaus

->filename "test.cc"
#include "ttt.h"

unsigned char a = 123, b;

int main()
{
   b = readchar(&a);
}

->filename "ttt.h"
#include "ttt.h"

unsigned char *t;

unsigned char readchar(unsigned char *ptr)
{
   unsigned char a;

   a = (*t);

   return(a);
}

->filename "ttt.cc"
#ifndef ttt_h
#define ttt_h ttt_h

extern unsigned char *t;

unsigned char readchar(unsigned char *ptr);

#endif

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