From:	user AT ts001d22 DOT cin-oh DOT concentric DOT net (Test User)
Newsgroups:	comp.os.msdos.djgpp
Subject:	Strange DJGPP bug
Date:	27 Sep 1998 04:10:07 PDT
Organization:	Concentric Internet Services
Lines:	29
Message-ID:	<slrn70rpos.5bh.user@ts001d22.cin-oh.concentric.net>
NNTP-Posting-Host:	ts001d22.cin-oh.concentric.net
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

Here's a short C program:

#include <stdio.h>

int main()
{
	char buffer[256];

	printf("Input: ");
	fgets(buffer, 255, stdin);
	printf("\nYou typed %s\n");
}


When compiled with the Linux version of GCC, this program
prints an Input: prompt. When the user types something and
presses ENTER, it then prints the string the user typed,
in the form of "\nYou typed %s\n", where \n is a newline and
%s is the string the user typed, including the trailing newline. 

When compiled with DJGPP, the program just sits there until
the user types something and presses ENTER. Then, the
program spews out the Input: prompt and the string the
user typed at the same time. For some reason, it executes
fgets() first, and then executes both printf's together. You
can't get it to print the prompt first, then call fgets(),
and then print the results. You can substitute fgets() for
your own elaborate loop system. You'll get the same result.

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