From:	Kevin Ashley <k DOT ashley AT ulcc DOT ac DOT uk>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: LARGE numbers.
Date:	Thu, 27 Aug 1998 18:29:06 +0100
Organization:	Posted via ULCC Internet Services
Lines:	36
Message-ID:	<35E59762.41C6@ulcc.ac.uk>
References:	<1103_904198596 AT isaacc>
NNTP-Posting-Host:	silver.ulcc.ac.uk
Mime-Version:	1.0
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

isaacc AT flash DOT net wrote:
> I want to store the following number (25834242042) as an int, I declare it as usual:
> 
> int var = 258342042;
> 
> yet the number is obviouslu too large to store as an integer (even an unsigned one).
> Subsequently I try to store it as both 'float' and 'double' - yet they wont even hold a number of
> this size!

Yes, this number (the 11-digit one that I presume you meant) is too
large for an int. You could use long long int (64-bit) as others have
pointed out, but this is gcc or architecture specific and the I/O libraries
did not fully support them when I last checked.

You can store such number in a double (you can do it in a float too, but
the accuracy won't be enough to represent it exactly.) Your problem
probably came because you wrote something like:

double dvar;

  	dvar = 25834242042;

This won't work because the RHS of this expression is an INTEGER constant.
We've already established this number's too big for an integer.
Instead, write:

  	dvar = 25834242042.;

That trailing dot turns it into a double constant.


----------------------------------------------------------------------------
Kevin Ashley                                       K DOT Ashley AT Ulcc DOT ac DOT uk
Special Projects Manager             http://www.ulcc.ac.uk/staff/Kevin+Ashley
ULCC                        ...ukc!ncdlab!K.Ashley (but probably not any more)
                      This is not a signature

- Raw text -