From:	"Martin Ambuhl" <mambuhl AT tiac DOT net>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: Why doesn't this work?
Date:	Wed, 13 May 1998 04:23:07 -0400
Organization:	Who wants to know?
Lines:	29
Message-ID:	<6jbl14$tv@news-central.tiac.net>
References:	<001101bd7ded$f8a31380$a74e08c3 AT arthur>
NNTP-Posting-Host:	p18.tc3.newyo.ny.tiac.com
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

Arthur wrote in message <001101bd7ded$f8a31380$a74e08c3 AT arthur>...
:Found a simple password program in QBASIC and as an exercise tried to
:convert it to C. So simple, you may say. It is, but for the life of me I
:could not get printf (of all things) to work.
:
:Source attached.
:
:Yes, I know that it is not optimised fully, but the routine is there and I
:know it works. Why does it not prompt you for your password until after you
:have typed it?
===============
Being allergic to the evils that can hide in encoded attachment, I have not
looked at your code.  The answer, however, is that input and output
streams are asynchronously buffered.  If you use a prompt with a
terminal \n, follow the printf with fflush(stdout);
==============
:
:It works if I use cprintf or scanf, so I assume that after printf is used,
:the text is not printed until some interrupt is set off (like a function
:call). I thought it was the simple "print to stdout" routine?
:
:James Arthur
:jaa AT arfa DOT clara DOT net
:
:
:

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