From:	Paul Shirley <Paul AT chocolat DOT foobar DOT co DOT uk>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: how to interpret this...
Date:	Mon, 2 Dec 1996 23:36:16 +0000
Organization:	DrinkSoft
Lines:	12
Distribution:	world
Message-ID:	<coUZoAAwf2oyEwxk@chocolat.foobar.co.uk>
References:	<57ve1o$rfk AT lyra DOT csx DOT cam DOT ac DOT uk>
NNTP-Posting-Host:	chocolat.foobar.co.uk
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To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

In article <57ve1o$rfk AT lyra DOT csx DOT cam DOT ac DOT uk>, "G.P. Tootell"
<gpt20 AT thor DOT cam DOT ac DOT uk> writes
>(a==b==c==0)

Because all the '==' operators have equal precedence C is allowed to
evaluate them in *any* order it likes.
About the only one it won't use is a==b && b==c && c==0 ;) since each
'==' evaluation reduces its 2 inputs to a boolean value (destroying the
value you planned on testing ;)

-- 
Paul Shirley

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