From:	mert0407 AT sable DOT ox DOT ac DOT uk (George Foot)
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: Help with Definition: int p=0,d[4]
Date:	8 Nov 1996 13:23:03 GMT
Organization:	Oxford University, England
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Message-ID:	<55vc7n$t9e@news.ox.ac.uk>
References:	<847448023 DOT 11346 DOT 0 AT ciscs19 DOT demon DOT co DOT uk>
NNTP-Posting-Host:	sable.ox.ac.uk
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

BDC Client Team (cs19 AT cityscape DOT co DOT uk) wrote:

: int p=0,d[4]

: It is obviously defining an integer variable 'p' and assigning a start value
: to it - can anyone help me with the right-hand side of the '=' sign ?  
: There is no reference to a variable 'd' in the rest of the code, so I assume 
: that, in this case, 'd'is recognized by the compiler as a function/constant 
: of some kind.

You'll kick yourself...

In C, if you write:

int p,d;

it declares 'p' and 'd' to be of type 'int'. If you write:

int p,d[4];

it declares 'p' to be an 'int' and 'd' to be a pointer to 5 'int's.

In C++, writing:

int p=0,d[4];

declares 'p' as and 'int' and sets it to zero, and also declares 'd' to 
be a pointer to 5 'int's. It's the same as:

int p=0;
int d[4];

The '=' sign has a higher precedence than the ','.

--
George Foot

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