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Date:	Sun, 16 Dec 2001 20:09:57 +0200
From:	"Eli Zaretskii" <eliz AT is DOT elta DOT co DOT il>
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To:	sandmann AT clio DOT rice DOT edu
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In-reply-to:	<10112161551.AA26332@clio.rice.edu> (sandmann@clio.rice.edu)
Subject:	Re: The Bash 2.05 fixinc.sh bug
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> From: sandmann AT clio DOT rice DOT edu (Charles Sandmann)
> Date: Sun, 16 Dec 2001 09:51:23 -0600 (CST)
> > > 
> > > SHELL = /bin/sh
> > > all:
> > >         MAKE="$(MAKE)"
> > 
> > This probably means that the file it compains about is the temporary file 
> > created in $TMPDIR, which is then submitted to Bash for execution.  What 
> > is the exact error message printed when this Makefile is run?
> 
> This should just be a symbol substitution, ie make=make.

That's true, but how do you expect Make to know about that?  It
doesn't; all it sees is a command line with some shell magic (the `='
character), so it invokes Bash.  Shell invocation goes through
`system', which, in the case of Unixy shells, does that via temporary
files.  That's why I guessed that the problem is with the temporary
file: after all, that's the only file that seems to be involved.

Of course, this is all pure theory; I didn't have a chance to step
with a debugger into Make or the library and see if I remember this
stuff correctly.

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