Message-ID:	<3BC35FB1.FF1958C@earthlink.net>
From:	Martin Ambuhl <mambuhl AT earthlink DOT net>
Organization:	Nocturnal Aviation
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Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: compiler doesn't catch missing semicolon after struct
References:	<c3114d1f DOT 0110091227 DOT 17603d3b AT posting DOT google DOT com>
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Date:	Tue, 09 Oct 2001 20:33:27 GMT
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To:	djgpp AT delorie DOT com
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Reply-To:	djgpp AT delorie DOT com

tenbux wrote:
> 
> Hi all,
> 
> I was working on a fairly simple lab for a CS class, and using DJGPP
> to compile and test my programs. Here is some sample code I had
> written:
> 
> #include <stdio.h>
> 
> struct bit {
>   int bit;
>   struct bit *next;
> }
> 
> main(int argc, char *argv[])
> {
>   int x;
>   FILE *in, *out;
> 
>   if (argc < 3) {
>     puts("Usage: binprint <numbers> <output>");
>     return;
>   }
> 
>   if ((in = fopen(argv[1], "r")) == NULL) {
>     printf("Error opening input file: %s\n", argv[1]);
>     return;
>   }
> 
> You'll notice that there is no semicolon after the struct declaration
> (as is required). But gcc didn't catch this, instead it warned me
> about main not being declared as int. 

gcc caught it.  You declared main as returning a struct bit instead of
an int.  It told you about, but ...

> So when I ran the binary with no
> arguments, 

you ignored the warning and got what you deserved.

> Is this a current bug or is it supposed
> to act that way? :)

Don't blame the compiler for your errors.

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