From:	"Edmund Horner" <ejrh AT paradise DOT net DOT nz>
Newsgroups:	comp.os.msdos.djgpp
References:	<8ps0im$f84$1 AT mulga DOT cs DOT mu DOT OZ DOT AU>
Subject:	Re: keyboard int 9 and djgpp
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Date:	Sat, 16 Sep 2000 00:11:06 +1200
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To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp
Reply-To:	djgpp AT delorie DOT com

I'm not 100% sure, but I think CTRL-C keypresses are handled under another
interrupt...  you might like to look under signals...

My advice is to set the SIGINT signal to a function that doesn't do
anything.  SIGINT is generated when CTRL-C is pressed...

But I am not sure how this will interact with your keyboard handler.


"Alistair_P SHILTON" <apsh AT ecr DOT mu DOT oz DOT au> wrote in message
news:8ps0im$f84$1 AT mulga DOT cs DOT mu DOT OZ DOT AU...
> I've recently written (as part of an emulator) a keyboard handling
routine.
> It is a simple assembly program that hooks into interupt 9 and
> stores a key up/down (state) map in upper (non-visible) video memory.
> Modifier keys are passed to the old int9 handler, but all other keys are
> blocked.  My program (in DJGPP) spawns the handler and uses the up/down
> map for keyboard emulation.
>
> What I don't understand is how come control-c still works (ie. stops the
> program!).  I've tested the handler without djgpp, and control-c is
disabled
> ok, so why/how does djgpp allow it to continue operating even though the
> keystroke is (should be) blocked?  Am I missing something here?  Any
pointers
> would be greatly appreciated.
>
>
> ----------------------------------------------------
>
> thanks
>
> Alistair Shilton
>
> http://www.ee.mu.oz.au/pgrad/apsh
>
>
>

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