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| From: | cs AT vums DOT cz |
| Newsgroups: | comp.os.msdos.djgpp |
| Subject: | Interrupt enable |
| Date: | Tue, 20 Jun 2000 13:38:23 GMT |
| Organization: | Deja.com - Before you buy. |
| Lines: | 29 |
| Message-ID: | <8ins4d$6o0$1@nnrp1.deja.com> |
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| To: | djgpp AT delorie DOT com |
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
| Reply-To: | djgpp AT delorie DOT com |
Could you help me?
The following program (Borland C 3.1) works incorrectly on one
suspicious computer only:
main(void)
{ ...
setvect(8,Timer); // store to interrupt routine
...
}
void interrupt Timer(void)
{ ...
outport(0x20,0x20); // enable interrupt (work incorrectly)
}
On the other computers the program works correctly.
The suspicious computer parameters: 486DX4 AMIBIOS 1994. Include PCI
and ISA bus, PCI VGA and MS DOS 6.22. Other orograms runs on this
computer correctly.
Questions:
1. Is the statement (enable interrupt) "outport(0x20,0x20)" correct ?
2. How to solve a such problem ?
Thanks Karel
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