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| From: | "Michael Stewart" <mike AT reggin DOT freeserve DOT co DOT uk> |
| Newsgroups: | comp.os.msdos.djgpp |
| Subject: | Re: Using pointers |
| Date: | Fri, 7 May 1999 08:42:47 +0100 |
| Organization: | USENET UK |
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| To: | djgpp AT delorie DOT com |
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
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GiovanniB wrote in message ...
>
> When I declare a pointer (i.e. int* myptr) it's possible to use it in
>this way :
> for(int i = 0; i < n; i++)
> {
> myptr[i] = somenumber;
> }
>where n is a number big than biggest int ?
You can indeed treat a pointer as an array, in a sense thats what it is.
Just remember to allocate the memory.
/* C */
myptr = (int *) malloc (n * sizeof (int));
/* C++, I think this is how to do it */
myptr = new (int)[n];
Michael Stewart
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