From:	Jonathan Foster <jgf1 AT ukc DOT ac DOT uk>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: problem with readkey()
Date:	Thu, 16 Oct 1997 21:15:34 +0100
Organization:	University of Kent at Canterbury, England
Message-ID:	<344675E6.177A@ukc.ac.uk>
References:	<01bcda6c$d9e94d80$0200a8c0 AT ingo>
NNTP-Posting-Host:	dhcp2dd5.ukc.ac.uk
Mime-Version:	1.0
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To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

Ingo Ruhnke wrote:
> 
> I got here some simple code which dosen't run as I expect it to work:
>  if (readkey() == 'a') {
> 
> this didn't get me the info about that was pressed, it said every time 
> "a wasn't pressed", but if i modify it to this:
> 
>  char c;
>  if ((c = readkey()) == 'a') {
> the programm works fine. Can anybody tell me why this is so. And if
> i use getchar() instead of readkey() it also works like expected, 
> so were is the problem which this code.

I think allegro returns the scancode or similar data in the high byte
returned by readkey().

Assigning this to a "char" will lose the high byte, leaving the letter.

A more explicit way of coding this is:

  if ( (char)readkey() == 'a') {
OR
  if ( (readkey() & 0xFF) == 'a') {

Note the single "&" (bitwise and)

Hope this helps.

P.S. There is a mailing list for allegro - visit this site for how
to join:

http://www.talula.demon.co.uk/allegro/

-- 
   Jon Foster.

(1st Year Maths/Computer Science Student)

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