Sender: richdawe AT bigfoot DOT com Message-ID: <3711C84A.F7A5DB10@meridian22.net> Date: Mon, 12 Apr 1999 11:17:46 +0100 From: Richard Dawe X-Mailer: Mozilla 4.08 [en] (X11; I; Linux 2.2.1 i586) MIME-Version: 1.0 To: DooMWiz CC: djgpp AT delorie DOT com Subject: Re: which function can return the directory of the .exe ? References: <7elgcd$4bv$1 AT wanadoo DOT fr> <21EF89438D8F2E17 DOT 6E21802C5B5E8F7A DOT 0AAE947B36D0BDC6 AT library-proxy DOT airnews DOT net> Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit Reply-To: djgpp AT delorie DOT com Hello. DooMWiz wrote: > AFAIK, there is no function to return the directory of an application. Check out this info page - type at command prompt: info libc alpha fnsplit fnsplit() will give you components of the filename. Use it on argv[0] and you should be able to get the program's path. HTH -- ============================================================================== Rich Dawe - 4th-year MSci Physicist @ Bristol University, UK richdawe AT bigfoot DOT com, http://www.bigfoot.com/~richdawe/ ==============================================================================