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Date: Sun, 18 Apr 2004 19:12:03 -0400
To: Thomas L Roche <tlroche AT us DOT ibm DOT com>, cygwin AT cygwin DOT com
From: Larry Hall <cygwin-lh AT cygwin DOT com>
Subject: Re: [OT?] make bash script wait for called program to finish?
In-Reply-To: <OF8360AB8D.AF64EFE2-ON85256E7A.007A0B3E-85256E7A.007AB9B2@ us.ibm.com>
References: <OF8360AB8D DOT AF64EFE2-ON85256E7A DOT 007A0B3E-85256E7A DOT 007AB9B2 AT us DOT ibm DOT com>
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At 06:20 PM 4/18/2004, you wrote:
>How to make a bash script wait for a program that it calls to finish?
>Why I ask:
>
>Don't ask me why this process is structured this way, but, in order to
>install some code that I need in order to test my code, I hafta
>
>a wget an (executable) extractor and some (non-executable) binaries
>
>b run the extractor on the binaries. This runs some InstallShield UI
>  that no one I know seems to know how to script. This creates an
>  installer and a set of disk images.
>
>c run the installer on the images. Fortunately this part I know how to
>  script.
>
>What I'd really like to do is script the whole thing, because each
>step takes about 30 min, but step b eludes me. So what I'd like my
>script to do is
>
>0 wget
>
>1 launch the extractor UI, which I will briefly twiddle
>
>2 wait for the extractor to finish
>
>3 check that the installer and images were created
>
>4 run the installer on the images
>
>I know how to script everything but 2: how can I do that?
>
>Apologies if this is a FAQ: if so, please pass a pointer. If possible
>please post to me as well as the list, and TIA.


What did you try?  Should we assume that 'wait' didn't work for you?



--
Larry Hall                              http://www.rfk.com
RFK Partners, Inc.                      (508) 893-9779 - RFK Office
838 Washington Street                   (508) 893-9889 - FAX
Holliston, MA 01746                     


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