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| From: | "Adrian Smith" <Adrian AT atpelectronics DOT connectfree DOT co DOT uk> |
| Newsgroups: | comp.os.msdos.djgpp |
| References: | <396368E3 DOT 14602 DOT 6A4366 AT localhost> |
| Subject: | Re: [ot] - some basic stuff |
| Date: | Wed, 5 Jul 2000 08:50:45 +0100 |
| Lines: | 27 |
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| To: | djgpp AT delorie DOT com |
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
| Reply-To: | djgpp AT delorie DOT com |
Don't know if this applies to you, but in digital electronics, OR gives a 1
result for 1 OR 1 wheras XOR gives a 0 for 1 XOR 1. ??
OR XOR
0 0 = 0 0 0 = 0
0 1 = 1 0 1 = 1
1 0 = 1 1 0 = 1
1 1 = 1 1 1 = 0
<Leon AT caresystems DOT com DOT au> wrote in message
news:396368E3 DOT 14602 DOT 6A4366 AT localhost...
> On 5 Jul 2000, at 6:10, smile773 wrote:
>
> > bitwise OR of x and y x|y
> > Exclusive OR x and y x^y
>
> yeah but what is the difference?
> if i use | symbol
> does that mean if either bit is 1 then the result
> bit is 1
>
> but then what does the exclusive ^ thing does?
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