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Message-ID: | <4B97B788.2080206@redhat.com> |
Date: | Wed, 10 Mar 2010 08:15:20 -0700 |
From: | Eric Blake <eblake AT redhat DOT com> |
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To: | cygwin AT cygwin DOT com |
Subject: | Re: allow executing a path in backslash notation |
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--------------enig76B2242A2880C83CA79321C9 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: quoted-printable On 03/10/2010 03:54 AM, Andy Koppe wrote: >>> $ builtin exec "$WINDIR\system32\cmd.exe" /C echo ok >>> -bash: exec: C:\WINDOWS\system32\cmd.exe: not found >>> >> Is it me, or is the quoting all wrong? Doesn't backslash in the double >> quote (") acts as an escape character. i.e \s =3D s, \c =3D c etc. >=20 > http://www.gnu.org/software/bash/manual/bashref.html#Double-Quotes: > The backslash retains its special meaning only when followed by one of > the following characters: =E2=80=98$=E2=80=99, =E2=80=98`=E2=80=99, =E2= =80=98"=E2=80=99, =E2=80=98\=E2=80=99, or newline. That's bash's rules. According to POSIX, "\n" has undefined behavior. And in some other implementations, such as Solaris sh, "\n" is interpolated by the shell as a newline. Bash instead does the interpolation when you use $'\n'. But the moral of the story is that within "", it is only portable to use \ if it is followed by one of the four bytes specifically documented by POSIX. --=20 Eric Blake eblake AT redhat DOT com +1-801-349-2682 Libvirt virtualization library http://libvirt.org --------------enig76B2242A2880C83CA79321C9 Content-Type: application/pgp-signature; name="signature.asc" Content-Description: OpenPGP digital signature Content-Disposition: attachment; filename="signature.asc" -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.10 (GNU/Linux) Comment: Public key at home.comcast.net/~ericblake/eblake.gpg Comment: Using GnuPG with Fedora - http://enigmail.mozdev.org/ iEYEARECAAYFAkuXt4gACgkQ84KuGfSFAYAPXQCfTL0L72VA06Hv0wfj/8awIsxr KxcAnicur6gBAdODtuxdJoBnebXFk10w =7mDv -----END PGP SIGNATURE----- --------------enig76B2242A2880C83CA79321C9--
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