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| Date: | Thu, 31 Dec 2009 15:42:37 +0200 |
| Message-ID: | <1ef5a52f0912310542o7b81b938nc7efeb1582e1fa18@mail.gmail.com> |
| Subject: | Re: cygwin passes argv with preserved (") quote. and it is undesired result. |
| From: | Csaba Raduly <rcsaba AT gmail DOT com> |
| To: | cygwin AT cygwin DOT com, jojelino AT gmail DOT com |
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On Thu, Dec 31, 2009 at 10:00 AM, jojelino wrote:
> hi
> here is testcase to reproduce the problem
>
> #include <stdio.h>
> #include <assert.h>
> int main(int argc, char**argv)
> {
> printf("argv %s",argv[1]);
> open(argv[1],"r");
> assert(fp);
> return 0;
> }
> build
> make =A4=B1.txt in directory.
> and run in cmd.exe
> type,
> a "=A4=B1.txt"
>
> and it complains file can't be opened.
> and you can see argv[1] is passed with preserved quote (") although it is
> invoked in winshell
> it must be eliminted when it is transduced to cygwin environment.
>
> but when parent process is cygwin, it gives no complaint
>>strace a "=A4=B1.txt"
> in result, is it designed to do so?
Yes. "parent process is cygwin" probably means that a.exe was started
from bash. The quote character is special for bash; see for example
http://linux.about.com/od/bgb_guide/a/gdebgb30t03.htm
This means that when started from bash, a.exe gets what's inside the
quotes, without the quotes themselves. cmd.exe may behave differently.
Hope this helps,
Csaba
--=20
Life is complex, with real and imaginary parts
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