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Date: | Tue, 21 Apr 2009 18:13:37 +0200 |
From: | Spiro Trikaliotis <an-cygwin AT spiro DOT trikaliotis DOT net> |
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Subject: | Re: [1.7] Updated: cygwin-1.7.0-45 |
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Hello, * On Tue, Apr 21, 2009 at 05:23:34PM +0200 Corinna Vinschen wrote: > On Apr 14 19:08, Thomas Wolff wrote: > > On April 14, Corinna Vinschen wrote: [...] > This is a real problem. In the OEM codepages the 0xff character is a > non-breaking space. Unfortunately there's no way to distinguish between > the (signed) char value 0xff and EOF when it's put as argument into the > ctype functions. sed has a loop which loops over all blank characters > in the input, basically like this: > > do { > ch = inchar (); > } while (isblank (ch); > > As soon as inchar() is at the end of the input, it returns EOF == -1. And > then the loop never stops, because the character value -1 is a blank > character. > > However, this appears to be a generic problem with the character with > value 0xff. If char is signed, its value is -1 and it can't be > distinguished from EOF. > > The only solution for this problem is, AFAICS, to treat the character > 0xff as a non-character, for which all ctype functions return 0. No. The real solution is to define ch as int in the first place. This way, ch = 0xff is the printable character, while ch = -1 is EOF. Look at the prototypes of the functions in ctype.h, they all take int as an argument. And getchar(), getc() and getch() all return an int, not a char. There's a reason for this. Regards, Spiro. -- Spiro R. Trikaliotis http://opencbm.sf.net/ http://www.trikaliotis.net/ http://www.viceteam.org/ -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
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