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On Fri, Jan 11, 2008 at 12:13:59AM +0100, Sven K?hler wrote: >> bash -c "exec /bin/echo \$@" some arguments here >> >> and see what's printed; then read the bash man page for why this happens). > >Oh, that possibility was new to me. > >All i wonder, is why the "some" gets lost. Only "arguments here" is >printed. And actually i would like to argue, that "$@" instead of $@ >should be used. Because, as on linux, the arguments are taken to be argv[0 - 2]. bash -c "exec /bin/echo \"\$0\" \"\$@\"" will get you all of the arguments. cgf -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
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