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From: | Shankar Unni <shankarunni AT netscape DOT net> |
Subject: | Re: May g++ output windows-style paths instead of cygwin-style one? |
Date: | Tue, 16 Aug 2005 11:55:14 -0700 |
Lines: | 24 |
Message-ID: | <ddtcqm$mfr$1@sea.gmane.org> |
References: | <000301c5a23d$04f46f00$cf34000a AT sven> <4301AB44 DOT 7DDCB59B AT dessent DOT net> |
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Brian Dessent wrote: > Angel Tsankov wrote: > >>Is there any way I can force the cygwin build of g++ to output folders >>using windows style (e.g. c:\folder\file) instead of cygwin style >>(/cygdrive/c/folder/file) when writing dependency files (-MM option)? > > No, there's no way to do that. Actually, there is: if the input path names to gcc/g++ are windows-style, it will happily emit windows-style paths to the -M output: % gcc -M /cygdrive/c/Shankar/foo.c foo.o: /cygdrive/c/Shankar/foo.c % gcc -M c:/Shankar/foo.c foo.o: c:/Shankar/foo.c And just to remind the OP: "c:/Shankar" *IS* a windows-style name (the underlying Win32 API happily takes both \ and / as directory separators). So you just have to define the directories in your Makefile using Windows-style paths, and preferably use "/" to avoid escape-related problems.. -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
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