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Programming in Emacs Lisp

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What happens in a small buffer

If the buffer contains fewer than 10,000 characters, a slightly different computation is performed. You might think this is not necessary, since the first computation could do the job. However, in a small buffer, the first method may not put the cursor on exactly the desired line; the second method does a better job.

The code looks like this:

(/ (+ 10 (* (buffer-size) (prefix-numeric-value arg))) 10))

This is code in which you figure out what happens by discovering how the functions are embedded in parentheses. It is easier to read if you reformat it with each expression indented more deeply than its enclosing expression:

   (+ 10
       (prefix-numeric-value arg)))

Looking at parentheses, we see that the innermost operation is (prefix-numeric-value arg), which converts the raw argument to a number. This number is multiplied by the buffer size in the following expression:

(* (buffer-size) (prefix-numeric-value arg)

This multiplication creates a number that may be larger than the size of the buffer--seven times larger if the argument is 7, for example. Ten is then added to this number and finally the large number is divided by ten to provide a value that is one character larger than the percentage position in the buffer.

The number that results from all this is passed to goto-char and the cursor is moved to that point.

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  Copyright 2003   by The Free Software Foundation     Updated Jun 2003