Message-ID: <3DF984EB.8010102@earthlink.net>
From: Martin Ambuhl <mambuhl AT earthlink DOT net>
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Newsgroups: comp.os.msdos.djgpp
Subject: Re: simple inequality evaluation fails?!?!
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Date: Fri, 13 Dec 2002 06:58:04 GMT
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To: djgpp AT delorie DOT com
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Reply-To: djgpp AT delorie DOT com

Edd Dawson wrote:
> Hi,
> 
> I came across an unexpected result when executing a program I'm writing.
> After tracking it down in the source, I wrote a few lines of test code and
> found that a simple evaluation of an inequality was failing.
> Here is the small chunk of test code from the program I am writing:
> 
> //test code starts here
> 
> printf("\nRPP = %d\n", raysperpixel);
> if(raysperpixel < 1)
>      printf("%d is less than 1\n", raysperpixel);
> else
>      printf("%d is greater than or equal to 1\n", raysperpixel);
> 
> //test code ends here
> 
> raysperpixel is an int (i.e its defined properly).
> Here is the corresponding output:
> 
> RPP = -35
> -35 is greater than or equal to 1

I don't believe you.  Here is a compilable version of your code, together 
with the output:

#include <stdio.h>

int main(void)
{
     int raysperpixel = -35;
     printf("\nRPP = %d\n", raysperpixel);
     if (raysperpixel < 1)
         printf("%d is less than 1\n", raysperpixel);
     else
         printf("%d is greater than or equal to 1\n", raysperpixel);
     return 0;
}


RPP = -35
-35 is less than 1

> 
> This makes about as much sense as the program's output! Can anyone help me
> out? I'm pretty sure it's a bug, 

I'm pretty sure you've got some error in your code.