From: Martin Str|mberg <ams AT father DOT ludd DOT luth DOT se>
Newsgroups: comp.os.msdos.djgpp
Subject: Re: Why so?
Date: Thu, 26 Jul 2001 13:06:44 +0000 (UTC)
Organization: University of Lulea, Sweden
Lines: 58
Message-ID: <996152804.153539@queeg.ludd.luth.se>
References: <9jp3tu$vb6c$1 AT ID-89475 DOT news DOT dfncis DOT de>
X-Trace: news.luth.se 996152804 11720 130.240.16.109 (26 Jul 2001 13:06:44 GMT)
X-Complaints-To: abuse AT luth DOT se
User-Agent: tin/pre-1.4-981225 ("Volcane") (UNIX) (SunOS/4.1.4 (sun4m))
Cache-Post-Path: queeg.ludd.luth.se!unknown AT father DOT ludd DOT luth DOT se
X-Cache: nntpcache 2.4.0b5 (see http://www.nntpcache.org/)
To: djgpp AT delorie DOT com
DJ-Gateway: from newsgroup comp.os.msdos.djgpp
Reply-To: djgpp AT delorie DOT com

Sergey Kovalev <kos AT kbtem DOT by> wrote:
: Hi all!

: I have a code:

: #include <stdio.h>
: #include <stdlib.h>
: #include <conio.h>
: #include <string.h>

: int main()
: {
:   char *str;
:   str=(char*)malloc(10);

Here you allocate 10 bytes and let str point to those bytes.

:   clrscr();
:   str="01234";
:   puts(str);

Here you let str point at the constant string "01234". You just leaked
10 bytes of memory.

:   printf("%s\n",str);
:   strcat(str,"567");

Here you modify element number 5 (== '\0' == nul) and write three
characters beyond "01234". Note that even if you only did
``strcat(str,"5");'' you would try to modify a readonly string, which
isn't allowed.

:   puts(str);
:   printf("%s\n",str);
:   return 1;
: }

: Why this code produces following results?
: 01234
: 01234
: 01234567
: 67

: Other compilers give me:
: 01234
: 01234
: 01234567
: 01234567

Only (bad) luck.


Right,

						MartinS