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From: Martin Ambuhl <mambuhl AT earthlink DOT net>
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Subject: Re: ASCII codes
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Date: Tue, 20 Mar 2001 00:52:38 GMT
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jaystewart1 wrote:
> 
> Can you guys help me write a program that outputs two strings and their
> length, then outputs the two strings in alphabetical order?

Show us (better: show comp.lang.c or alt.comp.lang.learn.c-c++) your
attempt and we will try to help fix your code.

> 
> The array below represents the ASCII codes for a string. Can anyone help me
> write a program that outputs the corresponding string?
> 
> int x[] ={65,112,114,105,108,32,115,104,111,119,
>               101,114,115,32,98,114,105,110,103,32,77,97,
>               121,32,102,108,111,119,101,114,115,32,33,0};

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    int x[] =
        { 65, 112, 114, 105, 108, 32, 115, 104, 111, 119, 101, 114, 115,
        32, 98, 114, 105, 110, 103, 32, 77, 97, 121, 32, 102, 108,
        111, 119, 101, 114, 115, 32, 33, 0
    };
    char *y;
    size_t i;
    if (!(y = malloc(sizeof x / sizeof *x))) {
        printf("Damn!\n");
        exit(EXIT_FAILURE);
    }
    for (i = 0; i < sizeof x / sizeof *x; i++)
        y[i] = x[i];
    printf
        ("The 'correctness' of the following output depends\n"
         "on the implementation using ASCII, by no means\n"
         "guaranteed by the standard.  Here we go:\n %s\n\n", y);
    printf
        ("Note that 'y' in the above statement could not be replaced by\n"
         "(char *)x because x[0] interpreted as chars is \\%03o \\%03o\n",
         (char)*(char *)&x, (char)(*(1 + (char *)&x)));
    free(y);
    return 0;
}


The 'correctness' of the following output depends
on the implementation using ASCII, by no means
guaranteed by the standard.  Here we go:
 April showers bring May flowers !

Note that 'y' in the above statement could not be replaced by
(char *)x because x[0] interpreted as chars is \101 \000