From: yosuke AT ccwf DOT cc DOT utexas DOT edu () Newsgroups: comp.os.msdos.djgpp,comp.os.msdos.misc Subject: redir.exe question Followup-To: comp.os.msdos.djgpp Date: 13 Jul 2000 17:41:34 GMT Organization: The University of Texas at Austin; Austin, Texas Lines: 38 Message-ID: <8kkv0e$4co$1@geraldo.cc.utexas.edu> NNTP-Posting-Host: piglet.cc.utexas.edu X-Trace: geraldo.cc.utexas.edu 963510094 4504 128.83.42.61 (13 Jul 2000 17:41:34 GMT) X-Complaints-To: abuse AT cc DOT utexas DOT edu NNTP-Posting-Date: 13 Jul 2000 17:41:34 GMT X-Newsreader: TIN [version 1.2 PL2] To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Reply-To: djgpp AT delorie DOT com I have question about redir which came with djgpp. I tested following code. #include int main(){ printf("1: this is stdout\n"); fprintf(stderr,"2: this is stderr\n"); printf("3: this is stdout\n"); fprintf(stderr,"4: this is stderr\n"); } when I executed it, I get followin on screen. 1: this is stdout 2: this is stderr 3: this is stdout 4: this is stderr but when I go redir -eo a.exe > out or redir -o out -eo a.exe I got this in out. 2: this is stderr 4: this is stderr 1: this is stdout 3: this is stdout Is there any way not have stderr to be mixed into stdout? -- yosuke kimura Center for Energy and Environmental Resources The Univ. of Texas at Austin, USA