From: "Requiem" <ennui AT nettaxi DOT com>
Newsgroups: comp.os.msdos.djgpp
Subject: Re: Structs
Date: 25 Dec 1999 11:25:17 EST
Organization: Concentric Internet Services
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To: djgpp AT delorie DOT com
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Reply-To: djgpp AT delorie DOT com

I don't think so...I don't want query gold to return a static number, but a
variable attached to the struct.

foo.query_gold();  returns la;

Requiem
ennui AT nettaxi DOT com
> > How can I link two different structs to the same function, without
> declaring
> > the function in both structs.
> >
> > for example
> >
> > int query_gold();
> >
> > struct foo {
> > int la;
> > int pe;
> > }
> >
> > struct foo2 {
> > int la;
> > int pe;
> > }
> >
> > foo->query_gold();
> > foo2->query_gold();
> >
> > Thanks
> >
> > Requiem
> > iraemortis AT subdimension DOT com
> >
> >
>
> Consider...
>
> struct bar {
>   int query_gold () {
>     return 2;
>   }
> };
>
> struct foo : public bar {
>   int la;
>   int pe;
> };
>
> struct foo2 : public bar {
>   int la;
>   int pe;
> };
>
> #include <iostream.h>
>
> int main () {
>   cout << foo ().query_gold () << endl;
>   cout << foo2 ().query_gold () << endl;
>   return 0;
> }
>
> /*
> Yields...
> 2
> 2
> */
>
> Is that what you wanted??
>
> Regards
>
> Brian
>
>
> > How can I link two different structs to the same function, without
> declaring
> > the function in both structs.
> >
> > for example
> >
> > int query_gold();
> >
> > struct foo {
> > int la;
> > int pe;
> > }
> >
> > struct foo2 {
> > int la;
> > int pe;
> > }
> >
> > foo->query_gold();
> > foo2->query_gold();
> >
> > Thanks
> >
> > Requiem
> > iraemortis AT subdimension DOT com
> >
> >
>
> Consider...
>
> struct bar {
>   int query_gold () {
>     return 2;
>   }
> };
>
> struct foo : public bar {
>   int la;
>   int pe;
> };
>
> struct foo2 : public bar {
>   int la;
>   int pe;
> };
>
> #include <iostream.h>
>
> int main () {
>   cout << foo ().query_gold () << endl;
>   cout << foo2 ().query_gold () << endl;
>   return 0;
> }
>
> /*
> Yields...
> 2
> 2
> */
>
> Is that what you wanted??
>
> Regards
>
> Brian
>
>