From: "Tom" Newsgroups: comp.os.msdos.djgpp Subject: Re: Convert from basic_string to char *... Date: Mon, 4 Oct 1999 17:50:17 -0400 Lines: 52 Message-ID: <7tb715$brq$1@autumn.news.rcn.net> References: <7tb6c9$770$1 AT autumn DOT news DOT rcn DOT net> X-Trace: CfVNtThY5HWEWTROzHNGo5oQb7SuybT9BmmJKXcK/Q9to4i0AmQ5HQ== X-Complaints-To: abuse AT rcn DOT com NNTP-Posting-Date: 4 Oct 1999 21:43:01 GMT X-Newsreader: Microsoft Outlook Express 5.00.2314.1300 X-MSMail-Priority: Normal X-Priority: 3 X-MimeOLE: Produced By Microsoft MimeOLE V5.00.2314.1300 To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Reply-To: djgpp AT delorie DOT com The above program didn't work, but I still want to know how to do the bottom one. Thanks. And also add the following to the top: #include #include Tom wrote in message news:7tb6c9$770$1 AT autumn DOT news DOT rcn DOT net... > Is it possible to convert a string that was obtained using getline into a > char *? I know how to convert regular strings to char * but when I try a > line obtained from getline it says it can't convert basic_string to char *. > > _________________________ > int main() > { > char *test1 = "hello"; > string test2= "hi"; > > cout << test1 << endl; > cout << test2 << endl; > > test1 = test2; > > cout << test1; > return 0; > } > _______________________________ > > The above program works. I want to do the following without errors. > > int main() > { > string s; > char *b[500]; > int n = 0; > > ifstream inputfile("text.txt"); > while ( getline( inputfile, s) ) > { > b[++n] = s; > cout << b[n] << endl; > } > return 0; > } > ___________________ > > Is this possbile? Thanks. > >