From: remove_this_mimo AT restoel DOT net_and_this (mimo) Newsgroups: comp.os.msdos.djgpp Subject: new and nothrow() Date: Tue, 18 May 1999 20:34:16 GMT Organization: MimoLand Lines: 26 Message-ID: <3741c977.1974482@news.wanadoo.fr> NNTP-Posting-Host: tntaub161-71.abo.wanadoo.fr Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit X-Trace: wanadoo.fr 927059454 29927 164.138.207.71 (18 May 1999 20:30:54 GMT) X-Complaints-To: abuse AT wanadoo DOT fr NNTP-Posting-Date: 18 May 1999 20:30:54 GMT To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Reply-To: djgpp AT delorie DOT com ok, this is rather a philosophical question, but maybe someone could help me: i found in my code book a way to avoid try/throw/catch when allocating memory using new which returns simply 0 instead. it says: void *operator new(size_t,const nothrow &) throw(); (and the new[] operator too) so i tried to write the following: int *tab = new (nothrow()) int[nb]; after including or (i dont see a difference) the compiler reported: Error: no match for call to `(nothrow_t) ()' than i replaced the line by: int *tab = new (nothrow) int[nb]; and the compiler accepted it. first question: is this a fault in my codebook? second: does this ever return 0 (NULL)? thanx in advance mimo