Message-ID: <3714DC8F.726858F2@vortex.ufrgs.br>
Date: Wed, 14 Apr 1999 15:21:03 -0300
From: "Luciano R. M. Silva" <lrms AT vortex DOT ufrgs DOT br>
X-Mailer: Mozilla 4.51 [en] (Win95; I)
X-Accept-Language: en
MIME-Version: 1.0
Newsgroups: comp.os.msdos.djgpp
Subject: Re: Newbie question. Please help
References: <01be8371$2d0814c0$LocalHost AT aguia>
Content-Type: text/plain; charset=us-ascii
Content-Transfer-Encoding: 7bit
Lines: 27
NNTP-Posting-Host: irc.ez-poa.com.br
To: djgpp AT delorie DOT com
DJ-Gateway: from newsgroup comp.os.msdos.djgpp
Reply-To: djgpp AT delorie DOT com

Hi,

I think that should help:

Simply use clock(), it also uses the BIOS clock tick or use uclock() that also
(I guess) read the timer counter from the 8254  to get a better resolution.
To get the time in seconds just subtratec two times and divide by
CLOCKS_PER_SEC (or UCLOCKS_PER_SEC in case of uclock()).

#include <time.h>
.
.
.
clock_t t1, t2;
float tseconds;
.
.
.
t1 = clock();
.
.
.
t2 = clock();
tseconds = (t2  - t1) / (float)CLOCKS_PER_SEC;

Don't forget that BIOS timer tick have a resolution of 55ms (18.2Hz).