Message-Id: <360E34C7.387F@cableol.co.uk>
Date: Sun, 27 Sep 1998 13:51:19 +0100
From: Allens <allen DOT asjp AT cableol DOT co DOT uk>
Mime-Version: 1.0
To: Test User <user AT ts001d22 DOT cin-oh DOT concentric DOT net>
Cc: djgpp AT delorie DOT com
Subject: Re: Strange DJGPP bug
References: <slrn70rpos DOT 5bh DOT user AT ts001d22 DOT cin-oh DOT concentric DOT net>
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Test User wrote:
> 
> Here's a short C program:
> 
> #include <stdio.h>
> 
> int main()
> {
>         char buffer[256];
> 
>         printf("Input: ");
>         fgets(buffer, 255, stdin);
>         printf("\nYou typed %s\n");
> }
> 
> When compiled with the Linux version of GCC, this program
> prints an Input: prompt. When the user types something and
> presses ENTER, it then prints the string the user typed,
> in the form of "\nYou typed %s\n", where \n is a newline and
> %s is the string the user typed, including the trailing newline.
> 
> When compiled with DJGPP, the program just sits there until
> the user types something and presses ENTER. Then, the
> program spews out the Input: prompt and the string the
> user typed at the same time. For some reason, it executes
> fgets() first, and then executes both printf's together. You
> can't get it to print the prompt first, then call fgets(),
> and then print the results. You can substitute fgets() for
> your own elaborate loop system. You'll get the same result.

To save time switching between protected mode and dos, djgpp is 
buffered, so the easiest way to make it print something on the
screen is to add \n to the end of printf ("input:") line.

		Peter Allen