Reply-To: <arfa AT clara DOT net>
From: "Arthur" <arfa AT clara DOT net>
To: "DJGPP Mailing List" <djgpp AT delorie DOT com>
Subject: RE: please help {newbie}
Date: Thu, 30 Jul 1998 12:40:08 +0100
Message-ID: <000001bdbbae$ce26e100$044d08c3@arthur>
MIME-Version: 1.0
Content-Type: text/plain;
	charset="iso-8859-1"
Content-Transfer-Encoding: 7bit
Importance: Normal
In-Reply-To: <6pmncl$pph$1@osprey.global.co.za>
Precedence: bulk

> how do i read a file name to the program in the calling statement i.e.
> "c:\resolve test.txt"

For your main statement, if you use

	int main(int argc, char *argv[])

then argc is the number of parameters passed, and argv is an array of pointers to
each parameter. In your case, argv[0] would point to a string containing 'test.txt'.

I've never used it before, but I think what I've said is right.

James Arthur
jaa AT arfa DOT clara DOT net
ICQ#15054819