Newsgroups: comp.os.msdos.djgpp
From: Elliott Oti <oti AT phys DOT uu DOT nl>
Subject: Re: passing arg 1 of 'free' ....
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Date: Fri, 19 Jun 1998 14:50:00 GMT
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On Fri, 19 Jun 1998, Theo Landgraf wrote:

> i get this warning:
> 
> passing arg 1 of 'free' discards 'const' from pointer target type.
> 
> what does this mean?
> how can i solve it?


It means you are trying to delete (i.e. alter)  a pointer
after informing the compiler that you are going to do no such thing by
declaring the pointer as const.

const char *myptr; // means I am not going to alter myptr => myptr = const

free(myptr); // means please release the memory pointed to by myptr
             // and make myptr = NULL;

If you are going to alter myptr don't declare it as const char *, just as
char *.

Cheers,

  Elliott Oti
  kamer 104, tel (030-253) 2516 (RvG)    
  http://www.fys.ruu.nl/~oti