From: degiorgi AT inf DOT ethz DOT ch (Daniele Degiorgi) Newsgroups: comp.os.msdos.djgpp Subject: Re: A newbie question: out to print out value of doubles? Date: 16 Dec 1996 14:13:27 GMT Organization: Dept. Informatik, Swiss Federal Institute of Technology Lines: 57 Message-ID: <593le7$lmb@neptune.ethz.ch> References: Reply-To: degiorgi AT inf DOT ethz DOT ch NNTP-Posting-Host: fido.inf.ethz.ch To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp In article , Miguel Murillo writes: > > >On Sat, 7 Dec 1996, Richard Adams wrote: > >> Hi. I have a question. I'm new to C. I'm writing an application that >> needs the extra precison of double-length floating point numbers >> rather than the single-precision float type. I'd like to be able to >> print out the double-floating-point variables, but how? I have tried >> the following but it doesn't work: >> >> #include >> #include >> >> void main(void) >> { >> double a=3.125978724; >> >> >> printf("The variable a is:\n\t"); >> fprintf ("%f\n", &a); > fprintf("%lf\n",a); This will generate the same error as fprintf needs a FILE pointer as 1 parameter. Thus use fprintf(stdout,"%f\n",a); or simply printf("%f\n",a); > > > /* Non pointer in printf, fprintf */ > /* fscanf("%lf",&a); */ /* scanf(... ot fscanf(stdin,... */ > /* pointer in scanf, fscanf */ > > >> >> return; >> } >> >> I get an "incompatible pointer type" warning. How can I print out the >> value of a double-precision floating point variable? Any help at all >> will be greatly appreciated...:) Thank you!! >> >> -Richard Adams >> radams AT mail DOT diac DOT com >> > >Good luck ! > Miguel Murillo > > Daniele