From: jj AT hermes DOT bouw DOT tno DOT nl (Jos Jansen)
Subject: execl in djgpp doesn't work!?
To: djgpp AT sun DOT soe DOT clarkson DOT edu
Date: Wed, 25 Nov 92 16:34:23 MET

	We try to use the execl call to get another programming running.

	Whatever we try for pathnames, it fails. From the documentation
	we expected it to work. Are we overlooking something?

	program: (t.c)
main()
{
  char *args[3];
  args[2] = args[1] = (char *) 0;
  execl( "go32", "ci30", (char *) 0 );
  execl( "ls", "ls", (char *) 0 );
  printf( "c:\\ubin\\ls.exe\n" );
  execl( "c:\\ubin\\ls.exe\n", "ls", (char *) 0 );
  printf( "c:\\ubin\\ls\n" );
  execl( "c:\\ubin\\ls\n", "ls", (char *) 0 );
  printf( "c:/ubin/ls.exe\n" );
  execl( "c:/ubin/ls.exe\n", "ls", (char *) 0 );
  printf( "c:/ubin/ls\n" );
  execl( "c:/ubin/ls\n", "ls", (char *) 0 );
  printf( "a.out\n" );
  execl( "a.out", "a.out", (char *) 0 );
  printf( "go32 a.out\n" );
  execl( "go32", "a.out", (char *) 0 );
  printf( "a.exe\n" );
  execl( "a.exe", "a.exe", (char *) 0 );
  args[0] = "ci30";
  printf( "execv %s\n", args[0] );
  execv( args[0], args );
  args[0] = "a.exe";
  printf( "execv %s\n", args[0] );
  execv( args[0], args );
  args[0] = "a.out";
  printf( "execv %s\n", args[0] );
  execv( args[0], args );
  printf( "exec failure\n" );
}

Compiled with

gcc t.c

Run with

go32 a.out

We also tried to stub it with copy <..>stub.exe/b+a.out a.exe to get an
executable a.exe

What are we doing wrong??

Jos Jansen
jj AT bouw DOT tno DOT nl