From: "Tim Van Holder" To: Subject: RE: Where does gcc -o foo make foo.exe Date: Sat, 13 Jan 2001 01:30:55 +0100 Message-ID: MIME-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook IMO, Build 9.0.2416 (9.0.2910.0) X-MimeOLE: Produced By Microsoft MimeOLE V5.50.4133.2400 In-reply-to: <20010112223359.497.qmail@lauras.lt> Importance: Normal Content-Transfer-Encoding: 8bit X-MIME-Autoconverted: from quoted-printable to 8bit by delorie.com id TAA25757 Reply-To: djgpp-workers AT delorie DOT com Errors-To: nobody AT delorie DOT com X-Mailing-List: djgpp-workers AT delorie DOT com X-Unsubscribes-To: listserv AT delorie DOT com Precedence: bulk > Sorry if this is a FAQ, but can anybody tell > where exactly in DJGPP toolchain was added support > for making foo.exe if only '-o foo' is given for GCC? > Is it specs, compiler driver, or somewhere else? > > The reason I'm asking - I've installed GCC 2.97 as > a default compiler to see what breaks. And it makes > only unstubbed images, if just -o foo is given. I want > to fix it. IIRC, ld uses coff-go32-exe as default, causing the output file 'foo' to be an exe in disguise. If gcc -o foo produces a bare coff file, you're probably not using the latest ld. The djgpp specs file adds a call to stubify to link_command, causing gcc -o foo to generate a foo.exe as well ("stubify foo" gives foo.exe, as does stubify foo.exe).