Date: Wed, 22 Mar 2000 10:25:22 +0200 (IST) From: Eli Zaretskii X-Sender: eliz AT is To: Hans-Bernhard Broeker cc: djgpp-workers AT delorie DOT com Subject: Re: Unnormals??? In-Reply-To: Message-ID: MIME-Version: 1.0 Content-Type: TEXT/PLAIN; charset=US-ASCII Reply-To: djgpp-workers AT delorie DOT com Errors-To: dj-admin AT delorie DOT com X-Mailing-List: djgpp-workers AT delorie DOT com X-Unsubscribes-To: listserv AT delorie DOT com Precedence: bulk On Mon, 20 Mar 2000, Hans-Bernhard Broeker wrote: > > "Intel Architecture Software Developer's Manual", v.1 "Basic > > Architecture" (I downloaded it from their site as 24319002.pdf, but that > > was quite a while ago), Section 7.6, Table 7-18. The Result column only > > mentions a real indefinite if neither of the operands is a NaN. Your > > case appears to be covered by the third possible combination (two QNaNs), > > whose result should be a QNaN, i.e. either with the sign bit reset or > > with a mantissa that doesn't fit the real indefinite description. > > It's not just 'a QNaN'. You get 'the QNaN with the bigger significand' > (i.e. mantissa), according to my book. Yes, but in this case the mantissas were identical. > Thinking about, this seems to imply > that the sign bit of the QNaN with the (absolutely) bigger significand is > just copied as-is. How do you deduce that? The manual keeps suspicious silence about the sign bit.